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    How p^n =np^n-1 p why is this extra p added
    Davneet Singh's image
    Davneet Singh

    Hi Dipankar, 

    We are differentiating with respect to x, 

    So, 

    If there was x, 
    d(x^2)/dx = 2 x^2-1 dx/dx = 2x 

    But since here it is p^n
    We write

    d(p^n)/dx = np^n-1 d(p)/dx

    Written on Feb. 15, 2017, 7:02 p.m.

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